First, address the alternating decimal as a continued number. Use a few iterations (it doesn’t amount absolutely how abounding are used).

Give this cardinal a name ( ):

1 chiffre recurs, so accumulate by 10.

So,

Subtracting these equations gives:

So,

Multiplying both abandon by 10 gives:

Dividing both abandon by 90, (to get the amount of ):

2 is a accepted agency of 26 and 90, so:

as a atom is .

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